Talk:Web Science/Part1: Foundations of the web/Ethernet/Minimum package length vs maximum cable length/quiz

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what about wave propagation delay[edit source]

The entire idea behind the min 46 bytes length was to occupy the entire channel.in the example wave propagation is happening at the rate of 3m/s per bit. This means time t =1s bits on wire =1 wave distance = 3m time t =2s bits on wire =2 wave distance = 6m this continues until time t=512s bits on wire=512 wave distance = 1500m

which mean a device B 1.5km apart will only know about the wave after 512 seconds. This means it takes us 512 seconds to fully occupy the channel. if device B transmits during this interval it will most likely result in garbled data. So how did having a min length help me in this scenario.

yes once device B receives the first bit he will remain blocked until 512 seconds because of the continuous transmission from the sender. --115.242.152.216 (discuss) 09:06, 20 June 2015 (UTC)

question1[edit source]

for question number 1 either you choose first or second option it will says you are wrong!!! --141.26.69.70 (discuss) 16:26, 26 October 2016 (UTC)

SPOILER ALERT:

You have to choose both options, since 10 nanoseconds = 0.00000001 seconds = 10^-8 seconds. --80.144.203.204 (discuss) 17:22, 28 October 2016 (UTC)

Quiz questions[edit source]

Can we please discuss the detailed solutions for the above 3 questions. --Msaha.kob (discusscontribs) 17:58, 26 October 2018 (UTC)