Talk:Web Science/Part1: Foundations of the web/Ethernet/Minimum package length vs maximum cable length/quiz

what about wave propagation delay

The entire idea behind the min 46 bytes length was to occupy the entire channel.in the example wave propagation is happening at the rate of 3m/s per bit. This means time t =1s bits on wire =1 wave distance = 3m time t =2s bits on wire =2 wave distance = 6m this continues until time t=512s bits on wire=512 wave distance = 1500m

which mean a device B 1.5km apart will only know about the wave after 512 seconds. This means it takes us 512 seconds to fully occupy the channel. if device B transmits during this interval it will most likely result in garbled data. So how did having a min length help me in this scenario.

yes once device B receives the first bit he will remain blocked until 512 seconds because of the continuous transmission from the sender. --115.242.152.216 (discuss) 09:06, 20 June 2015 (UTC)

question1

for question number 1 either you choose first or second option it will says you are wrong!!! --141.26.69.70 (discuss) 16:26, 26 October 2016 (UTC)

SPOILER ALERT:

You have to choose both options, since 10 nanoseconds = 0.00000001 seconds = 10^-8 seconds. --80.144.203.204 (discuss) 17:22, 28 October 2016 (UTC)

Quiz questions

Can we please discuss the detailed solutions for the above 3 questions. --Msaha.kob (discuss • contribs) 17:58, 26 October 2018 (UTC)