This representation is inflated. The Boolean function is sufficiently represented by the red-yellow Euler diagram (A, D).
The green-blue Venn diagram (B, C) does not add information.
But the corresponding circles e.g. in barita are relevant.
So are those in the gap variants vidita and vanatu.
This is like barogi shown above, but with the additional information, that B and C are complements: .
This is a 4-ary Boolean function, whose bloatless part is the 2-ary barogi.
(It is a special case, that the arguments of the bloatless and bloat part are disjoint.)
This representation is also inflated. Only the red-yellow-brown Euler diagram (A, D, E) matters.
The green-blue Venn diagram (B, C) does not add information. But the corresponding circles in basiga are relevant.
The green-blue (B, C) and brown-magenta (E, F) Venn diagrams would be separate bundles, if they were not trisected by the red-yellow Euler diagram (A, D).
In the graph this is a multiplication, and in the formula it is a conjunction. Compare the filtrates.
Euler diagram and graph
layers of 3D Euler diagram
The 3-dimensional Euler diagram has 3*7 = 21 cells, 3*8 + 2*7 = 38 faces, 22 edges and 4 vertices.
The edges and vertices are two times the arrangement seen here. Compare bar.
One could get the impression, that brown and green are parallel, while brown and blue are not. But each cross could be flipped upside-down, without changing the topology.
Without the small bundle (F, G, H) the surrounding one would be just the red-yellow-brown Euler diagram (A, D, E), as in basori.
But as the small bundle is only in B, and not in C, the green and blue circles are also needed.
If the inner bundle were on its own, it would fall apart into the circles F and H. The circle G would just bisect that Boolean function, adding no information. But in the nested bundle, the circle G is relevant. Removing it would mean, that G implicitly bisects the whole Boolean function (including A...E). But actually it bisects only one cell of the surrounding bundle, namely the one where only B and D intersect.