# Interpolation and Extrapolation

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This course belongs to the track Numerical Algorithms in the Department of Scientific Computing in the School of Computer Science.

In this course, students will learn how to approximate discrete data. Different representations and techniques for the approximation are discussed.

## Discrete Data[edit]

Discrete data arises from measurements of or when is difficult or expensive to evaluate.

In general, discrete data is given by a set of nodes , and the function evaluated at these points: , .

In the following, we will refer to the individual nodes and function values as and respectively. The vectors of the nodes or function values are written as and respectively.

We will also always assume that the are *distinct*.

## Polynomial Interpolation[edit]

Although there are many ways of representing a function , polynomials are the tool of choice for interpolation. As the Taylor series expansion of a function around shows, every continuous, differentiable function has a polynomial representation

in which the are the exact weights.

If a function is assumed to be continuous and differentiable and we assume that it's derivatives are zero or of negligible magnitude for increasing , it is a good idea to approximate the function with a polynomial.

Given distinct nodes , at which the function values are known, we can construct an **interpolating polynomial** such that for all . Such an interpolating polynomial with degree is unique. However infinitely many such polynomials can be found with degree .

*Any nice way of deriving the interpolation error?*

## The Vandermonde Matrix[edit]

By definition as given above, our polynomial

must interpolate the function at the nodes . This leads to the following system of linear equations in the coefficients :

We can re-write this system of linear equation in matrix notation as

where is the vector of the , coefficients and is the so-called moment matrix or Vandermonde matrix with

or

This linear system of equations can be solved for using Gauss elimination or other methods.

The following shows how this can be done in Matlab or GNU Octave.

% declare our function f f = inline('sin(pi*2*x)','x') % order of the interpolation? n = 5 % declare the nodes x_i as random in [0,1] x = rand(n,1) % create the moment matrix M = zeros(n) for i=1:n M(:,i) = x.^(i-1); end % solve for the coefficients a a = M \ f(x) % compute g(x) g = ones(n,1) * a(1) for i=2:n g = g + x.^(i-1)*a(i); end; % how good was the approximation? g - f(x)

However practical it may seem, the Vandermonde matrix is not especially suited for more than just a few nodes. Due to it's special structure, the Condition Number of the Vandermode matrix increases with .

If in the above example we set and compute with

% solve for the coefficients a a = inv(M) * f(x)

the approximation is only good up to 10 digits. For it is accurate only to one digit.

We must therefore consider other means of computing and/or representing .

## Lagrange Interpolation[edit]

Given a set of nodes , , we define the ^{th} Lagrange Polynomial as the polynomial of degree that satisifies

*Maybe add a nice plot of a Lagrange polynomial over a few nodes?*

The first condition, namely that for can be satisfied by construction. Since every polynomial of degree can be represented as the product

where the are the roots of and is some constant, we can construct as

- .

The polynomial is of order and satisifies the first condition, namely that for .

Since, by construction, the roots of are at the nodes , , we know that the value of cannot be zero. This value, however, should be by definition. We can enforce this by scaling by :

If we insert any , into the above equation, the nominator becomes and the first condition is satisified. If we insert , the nominator and the denominator are the same and we get , which means that the second condition is also satisfied.

We can now use the Lagrange polynomials to construct a polynomial of degree which interpolates the function values at the points .

Consider that, given the definition of ,

- .

Therefore, if we define as

then for all . Since the are all of degree , the weighted sum of these polynomials is also of degree .

Therefore, is the polynomial of degree which interpolates the values at the nodes .

The representation with Lagrange polynomials has some advantages over the monomial representation described in the previous section.

First of all, once the Lagrange polynomials have been computed over a set of nodes , computing the interpolating polynomial for a new set of function values is trivial, since these only need to be multiplied with the Lagrange polynomials, which are independent of the .

Another advantage is that the representation can easily be extended if additional points are added. The Lagrange polynomial , obtained by adding a point to the interpolation, is

- .

Only the new polynomial would need to be re-computed from scratch.

In the monomial representation, adding a point would involve adding an extra line and column to the Vandermonde matrix and re-computing the solution.

*Add a word on Barycentric interpolation to facilitate adding points.*

## Newton Interpolation[edit]

Given a set of function values evaluated at the nodes , the Newton polynomial is defined as the sum

where the are the Newton basis polynomials defined by

.

An interpolation polynomial of degree n+1 can be easily obtained from that of degree n by just adding one more node point and adding a polynomial of degree n+1 to .

The Newton form of the interpolating polynomial is particularly suited to computations by hand, and underlies Neville's algorithm for polynomial interpolation. It is also directly related to the exact formula for the error term . Any good text in numerical analysis will prove this formula and fully specify Neville's algorithm, usually doing both via divided differences.

(Should link to error formula, divided differences and Neville's algorithm, adding articles where they don't exist)

## Interpolation error[edit]

When interpolating a given function *f* by a polynomial of degree *n* at the nodes *x*_{0},...,*x*_{n} we get the error

where

is the notation for divided differences.

If *f* is *n* + 1 times continuously differentiable on a closed interval *I* and be a polynomial of degree at most n that interpolates *f* at *n* + 1 distinct points {*x*_{i}} (*i*=0,1,...,n) in that interval. Then for each x in the interval there exists in that interval such that

The above error bound suggests choosing the interpolation points *x*_{i} such that the product | Π (*x* − *x*_{i}) | is as small as possible.

### Proof[edit]

Let's set the error term is

and set up a auxiliary function and the function is

where

and

Since are roots of function f and , so we will have

and

Then has n+2 roots. From Rolle's theorem, has n+1 roots, then has one root , where is in the interval I.

So we can get

Since is a polynomial of degree at most n, then

Thus

Since is the root of , so

Therefore

.

## Switching Between Representations[edit]

## Arbitrary Basis Functions[edit]

## Piecewise Interpolation / Splines[edit]

## Radial Basis Functions[edit]

## Extrapolation[edit]

Interpolation is the technique of estimating the value of a function for any intermediate value of the independent variable while the process of computing the value of the function outside the given range is called extrapolation.

Caution must be used when extrapolating, as assumptions outside the data region (linearization, general shape and slope) may breakdown.