Physics equations/06-Uniform Circular Motion and Gravitation/Q:friction/More practice

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1

A merry-go-round has an angular frequency, , equal to 0.174 rad/sec. How many minutes does it take to complete 8.5 revolutions?

a) 3.87 minutes.
b) 4.45 minutes.
c) 5.12 minutes.
d) 5.88 minutes.
e) 6.77 minutes.

2

A merry-go round has a period of 0.34 minutes. What is the centripetal force on a 89.6 kg person who is standing 2.25 meters from the center?

a) 16.6 newtons.
b) 19.1 newtons.
c) 22 newtons.
d) 25.3 newtons.
e) 29.1 newtons.

3

A merry-go round has a period of 0.34 minutes. What is the minimum coefficient of static friction that would allow a 89.6 kg person to stand2.25 meters from the center, without grabbing something?

a) 0.019
b) 0.022
c) 0.025
d) 0.029
e) 0.033

4

What is the gravitational acceleration on a plant that is 2.67 times more massive than Earth, and a radius that is 1.74 times greater than Earths?

a) 5.7 m/s2
b) 6.5 m/s2
c) 7.5 m/s2
d) 8.6 m/s2
e) 9.9 m/s2

5

What is the gravitational acceleration on a plant that is 1.95 times more dense than Earth, and a radius that is 2.12 times greater than Earth's?

a) 40.5 m/s2
b) 46.6 m/s2
c) 53.6 m/s2
d) 61.6 m/s2
e) 70.9 m/s2


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