# Physics equations/05-Friction, Drag, and Elasticity/Q:thirdLaw/Testbank

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## Contents

## a05frictDragElast_3rdLaw_v1[edit]

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===2=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.4 kg, and the mass of m<sub>2</sub> is 2.3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 174 N, what is the tension in the connecting string? Assume no friction is present.} -a) 84.2 N -b) 96.8 N -c) 111.3 N +d) 128 N -e) 147.2 N ===3=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 7 kg, and the mass of m<sub>2</sub> is 3.6 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 153 N, what is the tension in the connecting string? Assume no friction is present.} -a) 66.4 N -b) 76.4 N -c) 87.9 N +d) 101 N -e) 116.2 N ===4=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.7 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 101 N, what is the tension in the connecting string? Assume no friction is present.} -a) 55.6 N -b) 64 N +c) 73.6 N -d) 84.6 N -e) 97.3 N ===5=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.4 kg, and the mass of m<sub>2</sub> is 3.9 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 136 N, what is the tension in the connecting string? Assume no friction is present.} +a) 79 N -b) 90.8 N -c) 104.4 N -d) 120.1 N -e) 138.1 N ===6=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.1 kg, and the mass of m<sub>2</sub> is 2.8 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 148 N, what is the tension in the connecting string? Assume no friction is present.} +a) 95.5 N -b) 109.9 N -c) 126.4 N -d) 145.3 N -e) 167.1 N ===7=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.4 kg, and the mass of m<sub>2</sub> is 2.3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 138 N, what is the tension in the connecting string? Assume no friction is present.} -a) 84.2 N +b) 96.8 N -c) 111.3 N -d) 128 N -e) 147.2 N ===8=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.5 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 141 N, what is the tension in the connecting string? Assume no friction is present.} -a) 58.2 N -b) 67 N -c) 77 N -d) 88.6 N +e) 101.8 N ===9=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.1 kg, and the mass of m<sub>2</sub> is 3.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 135 N, what is the tension in the connecting string? Assume no friction is present.} -a) 45.8 N -b) 52.6 N -c) 60.5 N -d) 69.6 N +e) 80.1 N ===10=== {<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.4 kg, and the mass of m<sub>2</sub> is 3.7 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 135 N, what is the tension in the connecting string? Assume no friction is present.} -a) 74.4 N +b) 85.5 N -c) 98.4 N -d) 113.1 N -e) 130.1 N

## a05frictDragElast_3rdLaw_v1[edit]

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===2=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.4 kg, m<sub>2</sub> = 2.3 kg, and F<sub>ext</sub> = 174 N), what is the acceleration? Assume no friction is present. } +a) 20 m/s<sup>2</sup> -b) 23 m/s<sup>2</sup> -c) 26.5 m/s<sup>2</sup> -d) 30.4 m/s<sup>2</sup> -e) 35 m/s<sup>2</sup> ===3=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 7 kg, m<sub>2</sub> = 3.6 kg, and F<sub>ext</sub> = 153 N), what is the acceleration? Assume no friction is present. } -a) 12.6 m/s<sup>2</sup> +b) 14.4 m/s<sup>2</sup> -c) 16.6 m/s<sup>2</sup> -d) 19.1 m/s<sup>2</sup> -e) 22 m/s<sup>2</sup> ===4=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.7 kg, m<sub>2</sub> = 2.5 kg, and F<sub>ext</sub> = 101 N), what is the acceleration? Assume no friction is present. } -a) 6.3 m/s<sup>2</sup> -b) 7.2 m/s<sup>2</sup> -c) 8.3 m/s<sup>2</sup> -d) 9.5 m/s<sup>2</sup> +e) 11 m/s<sup>2</sup> ===5=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.4 kg, m<sub>2</sub> = 3.9 kg, and F<sub>ext</sub> = 136 N), what is the acceleration? Assume no friction is present. } -a) 12.7 m/s<sup>2</sup> +b) 14.6 m/s<sup>2</sup> -c) 16.8 m/s<sup>2</sup> -d) 19.3 m/s<sup>2</sup> -e) 22.2 m/s<sup>2</sup> ===6=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.1 kg, m<sub>2</sub> = 2.8 kg, and F<sub>ext</sub> = 148 N), what is the acceleration? Assume no friction is present. } -a) 14.2 m/s<sup>2</sup> -b) 16.3 m/s<sup>2</sup> +c) 18.7 m/s<sup>2</sup> -d) 21.5 m/s<sup>2</sup> -e) 24.8 m/s<sup>2</sup> ===7=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.4 kg, m<sub>2</sub> = 2.3 kg, and F<sub>ext</sub> = 138 N), what is the acceleration? Assume no friction is present. } -a) 10.2 m/s<sup>2</sup> -b) 11.8 m/s<sup>2</sup> -c) 13.6 m/s<sup>2</sup> -d) 15.6 m/s<sup>2</sup> +e) 17.9 m/s<sup>2</sup> ===8=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.5 kg, m<sub>2</sub> = 2.5 kg, and F<sub>ext</sub> = 141 N), what is the acceleration? Assume no friction is present. } -a) 9 m/s<sup>2</sup> -b) 10.3 m/s<sup>2</sup> -c) 11.8 m/s<sup>2</sup> -d) 13.6 m/s<sup>2</sup> +e) 15.7 m/s<sup>2</sup> ===9=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.1 kg, m<sub>2</sub> = 3.5 kg, and F<sub>ext</sub> = 135 N), what is the acceleration? Assume no friction is present. } -a) 13.7 m/s<sup>2</sup> +b) 15.7 m/s<sup>2</sup> -c) 18.1 m/s<sup>2</sup> -d) 20.8 m/s<sup>2</sup> -e) 23.9 m/s<sup>2</sup> ===10=== {<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.4 kg, m<sub>2</sub> = 3.7 kg, and F<sub>ext</sub> = 135 N), what is the acceleration? Assume no friction is present. } +a) 13.4 m/s<sup>2</sup> -b) 15.4 m/s<sup>2</sup> -c) 17.7 m/s<sup>2</sup> -d) 20.3 m/s<sup>2</sup> -e) 23.4 m/s<sup>2</sup>

## a05frictDragElast_3rdLaw_v1[edit]

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===2=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 640 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.68 . The net mass of the (shoed) basketball team is 431 kg. What is the maximum coefficient of the barefoot boys if they lose?} -a) 0.313 -b) 0.344 -c) 0.378 -d) 0.416 +e) 0.458 ===3=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 625 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.54 . The net mass of the (shoed) basketball team is 445 kg. What is the maximum coefficient of the barefoot boys if they lose?} -a) 0.263 -b) 0.289 -c) 0.318 -d) 0.35 +e) 0.384 ===4=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 672 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.59 . The net mass of the (shoed) basketball team is 407 kg. What is the maximum coefficient of the barefoot boys if they lose?} -a) 0.295 -b) 0.325 +c) 0.357 -d) 0.393 -e) 0.432 ===5=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 664 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.53 . The net mass of the (shoed) basketball team is 418 kg. What is the maximum coefficient of the barefoot boys if they lose?} +a) 0.334 -b) 0.367 -c) 0.404 -d) 0.444 -e) 0.488 ===6=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 679 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.61 . The net mass of the (shoed) basketball team is 380 kg. What is the maximum coefficient of the barefoot boys if they lose?} -a) 0.31 +b) 0.341 -c) 0.376 -d) 0.413 -e) 0.454 ===7=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 616 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.71 . The net mass of the (shoed) basketball team is 388 kg. What is the maximum coefficient of the barefoot boys if they lose?} +a) 0.447 -b) 0.492 -c) 0.541 -d) 0.595 -e) 0.655 ===8=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 640 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.61 . The net mass of the (shoed) basketball team is 385 kg. What is the maximum coefficient of the barefoot boys if they lose?} -a) 0.303 -b) 0.334 +c) 0.367 -d) 0.404 -e) 0.444 ===9=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 692 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.61 . The net mass of the (shoed) basketball team is 406 kg. What is the maximum coefficient of the barefoot boys if they lose?} +a) 0.358 -b) 0.394 -c) 0.433 -d) 0.476 -e) 0.524 ===10=== {<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 616 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.68 . The net mass of the (shoed) basketball team is 421 kg. What is the maximum coefficient of the barefoot boys if they lose?} -a) 0.422 +b) 0.465 -c) 0.511 -d) 0.562 -e) 0.619

## a05frictDragElast_3rdLaw_v1[edit]

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===2=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.24 . But the team wins a game of tug of war due to their superior mass of 643 kg. They are playing against a 5 person basketball team with a net mass of 405 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.26 -b) 0.286 -c) 0.315 -d) 0.346 +e) 0.381 ===3=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.36 . But the team wins a game of tug of war due to their superior mass of 683 kg. They are playing against a 5 person basketball team with a net mass of 406 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.455 -b) 0.501 -c) 0.551 +d) 0.606 -e) 0.666 ===4=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.23 . But the team wins a game of tug of war due to their superior mass of 675 kg. They are playing against a 5 person basketball team with a net mass of 394 kg. What is the maximum coefficient of static friction of the basketball team? } +a) 0.394 -b) 0.433 -c) 0.477 -d) 0.524 -e) 0.577 ===5=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.35 . But the team wins a game of tug of war due to their superior mass of 614 kg. They are playing against a 5 person basketball team with a net mass of 405 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.439 -b) 0.482 +c) 0.531 -d) 0.584 -e) 0.642 ===6=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.33 . But the team wins a game of tug of war due to their superior mass of 663 kg. They are playing against a 5 person basketball team with a net mass of 422 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.39 -b) 0.428 -c) 0.471 +d) 0.518 -e) 0.57 ===7=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.38 . But the team wins a game of tug of war due to their superior mass of 671 kg. They are playing against a 5 person basketball team with a net mass of 438 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.481 -b) 0.529 +c) 0.582 -d) 0.64 -e) 0.704 ===8=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.23 . But the team wins a game of tug of war due to their superior mass of 607 kg. They are playing against a 5 person basketball team with a net mass of 429 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.269 -b) 0.296 +c) 0.325 -d) 0.358 -e) 0.394 ===9=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.21 . But the team wins a game of tug of war due to their superior mass of 683 kg. They are playing against a 5 person basketball team with a net mass of 389 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.277 -b) 0.305 -c) 0.335 +d) 0.369 -e) 0.406 ===10=== {<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.3 . But the team wins a game of tug of war due to their superior mass of 662 kg. They are playing against a 5 person basketball team with a net mass of 430 kg. What is the maximum coefficient of static friction of the basketball team? } -a) 0.42 +b) 0.462 -c) 0.508 -d) 0.559 -e) 0.615

## a05frictDragElast_3rdLaw_v1[edit]

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===2=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.9 kg, and the mass of m<sub>2</sub> is 3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 131 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.31, and that for m<sub>2</sub> the coefficient is 0.49 .} -a) 76.2 N +b) 87.6 N -c) 100.8 N -d) 115.9 N -e) 133.3 N ===3=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.7 kg, and the mass of m<sub>2</sub> is 3.1 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 137 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.34, and that for m<sub>2</sub> the coefficient is 0.47 .} -a) 56.7 N -b) 65.2 N -c) 74.9 N +d) 86.2 N -e) 99.1 N ===4=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.7 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 159 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.34, and that for m<sub>2</sub> the coefficient is 0.46 .} -a) 82 N -b) 94.3 N +c) 108.5 N -d) 124.8 N -e) 143.5 N ===5=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.9 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 165 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.35, and that for m<sub>2</sub> the coefficient is 0.44 .} -a) 68.3 N -b) 78.6 N -c) 90.4 N -d) 103.9 N +e) 119.5 N ===6=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.5 kg, and the mass of m<sub>2</sub> is 2.9 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 132 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.37, and that for m<sub>2</sub> the coefficient is 0.48 .} +a) 89.1 N -b) 102.5 N -c) 117.9 N -d) 135.5 N -e) 155.9 N ===7=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.8 kg, and the mass of m<sub>2</sub> is 3.3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 112 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.39, and that for m<sub>2</sub> the coefficient is 0.46 .} -a) 48.6 N -b) 55.9 N -c) 64.2 N +d) 73.9 N -e) 85 N ===8=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.5 kg, and the mass of m<sub>2</sub> is 3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 175 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.33, and that for m<sub>2</sub> the coefficient is 0.48 .} -a) 66.7 N -b) 76.7 N -c) 88.3 N -d) 101.5 N +e) 116.7 N ===9=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6 kg, and the mass of m<sub>2</sub> is 3.2 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 173 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.31, and that for m<sub>2</sub> the coefficient is 0.44 .} +a) 110.2 N -b) 126.7 N -c) 145.7 N -d) 167.6 N -e) 192.7 N ===10=== {<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.2 kg, and the mass of m<sub>2</sub> is 2.9 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 179 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.36, and that for m<sub>2</sub> the coefficient is 0.46 .} -a) 74.4 N -b) 85.5 N -c) 98.3 N +d) 113.1 N -e) 130.1 N