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Nonlinear finite elements/Timoshenko beams

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Timoshenko Beam

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Timoshenko beam.

Displacements

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Strains

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Principle of Virtual Work

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where

= shear correction factor

Taking Variations

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Take variation

Take variation

Take variation

Internal Virtual Work

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Integrate by Parts

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Get rid of derivatives of the variations.

Collect terms

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Euler-Lagrange Equations

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Constitutive Relations

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Then,

where

Equilibrium Equations

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Weak Form

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Finite element model

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Trial Solution

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Element Stiffness Matrix

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Choice of Approximate Solutions

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Choice 1

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= linear ()
= linear ()
= linear ().

Nearly singular stiffness matrix ().

Choice 2

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= linear ()
= quadratic ()
= linear ().

The stiffness matrix is (). We can statically condense out the interior degree of freedom and get a () matrix. The element behaves well.

Choice 3

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= linear ()
= cubic ()
= quadratic ()

The stiffness matrix is (). We can statically condense out the interior degrees of freedom and get a () matrix. If the shear and bending stiffnesses are element-wise constant, this element gives exact results.

Shear Locking

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Example Case

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Linear , Linear , Linear .

But, for thin beams,

If constant

Also

  1. Non-zero transverse shear.
  2. Zero bending energy.

Result: Zero displacements and rotations Shear Locking!

Recall

or,

If and constant

If there is only bending but no stretching,

Hence,

Also recall:

or,

If and constant, and no membrane strains

Hence,

Shape functions need to satisfy:


Example Case 1

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Linear , Linear , Linear .

  • First condition constant constant. Passes! No Membrane Locking.
  • Second condition linear constant. Fails! Shear Locking.

Example Case 2

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Linear , Quadratic , Linear .

  • First condition Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "http://localhost:6011/en.wikiversity.org/v1/":): {\displaystyle \implies} constant quadratic. Fails! Membrane Locking.
  • Second condition linear linear. Passes! No Shear Locking.

Example Case 3

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Quadratic , Quadratic , Linear .

  • First condition linear quadratic. Fails! Membrane Locking.
  • Second condition linear linear. Passes! No Shear Locking.

Example Case 4

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Cubic , Quadratic , Linear .

  • First condition quadratic quadratic. Passes! No Membrane Locking.
  • Second condition linear linear. Passes! No Shear Locking.

Overcoming Shear Locking

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Option 1

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  • Linear , linear , linear .
  • Equal interpolation for both and .
  • Reduced integration for terms containing - treat as constant.

Option 2

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  • Cubic , quadratic , linear .
  • Stiffness matrix is .
  • Hard to implement.