Joint Entrance Examination/AIEEE 2009/Q087 ENERGY CONSERVATION

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Original Question by 164.100.170.4 Here's the question... Q87. A thin uniform rod of length l and mass m is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is ω. Its centre of mass rises to a maximum height of (1)[1/6]Iω/g (2)[1/2]I2ω2/g (3)[1/6]I2ω2/g (4)[1/3]I2ω2/g Posted by 164.100.170.4 04:22, 25 September 2009 (UTC) Post a reply![1]

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Reply to the thread, posted by 164.100.170.4 Thread post Additional notes SOLUTION 3 Loss in kinetic energy = Gain in potential energy [1/2]Iω2 =mgh ⇒[1/2][ml2/3]ω2=mgh ⇒h=l2w2/6g These comments, along with the notes on the left, were contributed by 164.100.170.4 04:26, 25 September 2009 (UTC)

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