University of Florida/Egm4313/s12.team13.steinberg.r1

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R1.5A[edit | edit source]

Problem Statement[edit | edit source]

4.) Find the general solution to the following ODE and check the result by substitution.

Solution[edit | edit source]

The homogeneous characteristic equation for linear 2nd order ODE's with constant coefficients is


For the ODE in this problem, the characteristic equation becomes

To solve for the solutions, the discriminant to the quadratic equation must first be calculated.


Since the discriminant is negative, there will be two imaginary solutions to the ODE. The solutions can be obtained by solving the remainder of the quadratic formula.





The two distinct, linearly independent, homogeneous solutions for the case with two imaginary roots are



The homogeneous solution is


The final general solution is therefore


To check this result using substitution, we must take the first and second derivatives of the general solution to substitute back into the original ODE.



Substituting back into the original ODE gives


Since all terms cancel to 0, is a general solution to the original ODE.

Section 2 Lecture Notes