Teletraffic engineering/How does Internet telephony traffic differ/Solutions to Module 8

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Solution[edit]

a) dprop =


b) dtrans =


c) dprop + dtrans = +


d) At t=dtrans, the bit would have moved along the link a distance of:
d = S*dtrans
The link distance M is given by:
M = S*dprop
Since dprop > dtrans, the bit will still be on the link going towards the other end of the link.


e) At t = dtrans, the bit would have moved along the link a distance of:
d = S*dtrans
The link distance M is given by:
M = S*dprop
Since dprop < dtrans then M < d, hence the bit would have already reached the other end of the link