Power Generation/Diesel Power/Part4

If heat produced by _X kg of oil = Y KCal (where 1kWh = 860 KCal)

Then we can derive the overal power plant efficiency as:

${\eta }_{overall}={\frac {860KCal}{YKCal}}\times 100$ (in %) ... Equation 4.1

Then the engine efficiency becomes:

${\eta }_{engine}={\frac {\eta _{o}verall}{\eta _{a}lternator}}\times 100$(in %) ... Equation 4.2

Where:_ ${\eta }_{alternator}$ is specified by manufacturer