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Polynomial/K/Interpolation/Fact/Proof

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Proof

We prove the existence and consider first the situation where bj=0 for all ji for some fixed i. Then

(Xa1)(Xai1)(Xai+1)(Xan)

is a polynomial of degree n1, which at the points a1,,ai1,ai+1,,an has value 0. The polynomial

bi(aia1)(aiai1)(aiai+1)(aian)(Xa1)(Xai1)(Xai+1)(Xan)

has at these points still a zero, but additionally at ai, its value is bi. We denote this polynomial by Pi. Then

P=P1+P2++Pn

is the polynomial looked for, because for the point ai, we have

Pj(ai)=0

for ji and Pi(ai)=bi.

The uniqueness follows from fact.