# Ideas in Geometry/Instructive examples/Continued Fractions, Section 3.2

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3.2 #30

√5 To start note that 3 > √5 > 2

So this means that √5 = 2+ (√5-2) Where 2 is the whole number part and (√5-2) is the fractional part of √5.

In a simple continued fraction our numerator is 1. In order to get 1 in the numerator we must use the reciprocal 1/(√5-2).

From this point we want to separate the whole-number part and the fractional part and can do so by multiplying both the numerator and denominator by the conjugate (√5+2) 1 x (√5+2) = (√5+2) and (√5-2) x (√5+2) = (5-4)

When we put both the numerator and denominator together we get (√5+2)/1 or (√5+2)

Now we need to get our original fractional part from (√5+2) in order to continue our fraction and can do so by adding and subtracting 4 from (√5+2) 4+(√5+2-4)

Using the associative property we get the next part of our continued fraction 4+(√5-2)

Repeat these steps to get the continued fraction √5= 2+1/ (4+1/(4+1/(4+1/(4+1/....)