Proof
We write the
characteristic polynomial
of
as
-

where
does not occur in
as a linear factor, that is,
is the algebraic multiplicity of
. Then,
and
are
coprime,
and, due to
fact,
we have the decompositon
-

and
-
is a bijection. Moreover,
-

where the inclusion
is clear, and the other inclusion follows from the fact that higher powers of
do not annihilate further elements, by the bijectivity on
just mentioned. For the characteristic polynomial, we have, due to the direct sum decomposition according to
fact,
the relation
-

where
is the characteristic polynomial of
and
is the characteristic polynomial of
. Since
restricted to
is the zero mapping, the minimal polynomial of
and, hence, also the characteristic polynomial
are some power of
, say
-

where
-

In particular,
,
as
is a divisor of
. Assume that
.
Then
is a zero of
and
is an eigenvalue of
. But this is a contradiction to the fact that
is a bijection on this space.