Proof
We write the
characteristic polynomial
of as
-
where does not occur in as a linear factor, that is, is the algebraic multiplicity of . Then,
and
are
coprime,
and, due to
fact,
we have the decompositon
-
and
-
is a bijection. Moreover,
-
where the inclusion is clear, and the other inclusion follows from the fact that higher powerse of do not annihilate further elements, by the bijectivity on just mentioned. For the characteristic polynomial, we have, due to the direct sum decomposition according to
fact,
the relation
-
where is the characteristic polynomial of and is the characteristic polynomial of . Since restricted to is the zero mapping, the minimal polynomial of and, hence, also the characteristic polynomial are some power of , say
-
where
-
In particular,
,
as is a divisor of . Assume that
.
Then is a zero of and is an eigenvalue of . But this is a contradiction to the fact that is a bijection on this space.