Proof
Because of the condition and
fact,
the mapping has a nontrival
kernel.
Hence, this mapping is not
injective
and, due to
fact,
also not
surjective.
Therefore,
-
is a strict linear subspace of . It follows that there exists also a linear subspace
of dimension , which contains . For
,
we have
-
Hence, the image of belongs to , that is, is -invariant.