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Endomorphism/Eigenvalue/Invariant hyperplane/Fact/Proof

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Proof

Because of the condition and fact, the mapping has a nontrival kernel. Hence, this mapping is not injective and, due to fact, also not surjective. Therefore,

is a strict linear subspace of . It follows that there exists also a linear subspace of dimension , which contains . For , we have

Hence, the image of belongs to , that is, is -invariant.