Talk:PlanetPhysics/Momentum
Original TeX Content from PlanetPhysics Archive[edit source]
%%% This file is part of PlanetPhysics snapshot of 2011-09-01 %%% Primary Title: momentum %%% Primary Category Code: 45.05.+x %%% Filename: Momentum.tex %%% Version: 2 %%% Owner: pbruin %%% Author(s): pbruin %%% PlanetPhysics is released under the GNU Free Documentation License. %%% You should have received a file called fdl.txt along with this file. %%% If not, please write to gnu@gnu.org. \documentclass[12pt]{article} \pagestyle{empty} \setlength{\paperwidth}{8.5in} \setlength{\paperheight}{11in}
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In \htmladdnormallink{classical mechanics}{http://planetphysics.us/encyclopedia/MathematicalFoundationsOfQuantumTheories.html}, \emph{momentum} is the product of \htmladdnormallink{mass}{http://planetphysics.us/encyclopedia/Mass.html} and \htmladdnormallink{velocity}{http://planetphysics.us/encyclopedia/Velocity.html} of a moving \htmladdnormallink{object}{http://planetphysics.us/encyclopedia/TrivialGroupoid.html}. More precisely, the momentum of a particle or \htmladdnormallink{rigid body}{http://planetphysics.us/encyclopedia/RigidBody.html} with mass $m$ and velocity $v$ is defined as
$$ \mathbf{p}\equiv m\mathbf{v}. $$ For a collection of $n$ particles (or rigid bodies) moving with different velocities, the total momentum $\mathbf{p}$ is defined as the \htmladdnormallink{vector}{http://planetphysics.us/encyclopedia/Vectors.html} sum of the momenta of the particles, $\mathbf{p}_1,\mathbf{p}_2,\ldots,\mathbf{p}_n$: $$ \mathbf{p}\equiv\sum_{i=1}^n\mathbf{p}_i. $$ The SI unit of momentum is kilogram metre per second (kg m/s).
Momentum plays an important role in Newton's second law, which in its most concise formulation reads $$ \mathbf{F}=\mathbf{\dot p}, $$ expressing that the total force exerted on an object equals the time derivative of its momentum. In the special case that there are no forces acting on the object, we get back Newton's first law: $\mathbf{p}$ (and therefore $\mathbf{v}$) is constant. More generally, if in a \htmladdnormallink{system}{http://planetphysics.us/encyclopedia/GenericityInOpenSystems.html} consisting of a number of objects there are no external forces (i.e., the only forces present are those between the objects themselves), then Newton's third law implies that all the forces cancel each other, so that the total momentum is still constant.
This last observation leads to the idea of a \emph{conserved quantity}. It turns out that the law of conservation of momentum is equivalent to the invariance of the \htmladdnormallink{physical laws}{http://planetphysics.us/encyclopedia/PrincipleOfCorrespondingStates.html} under translations. This idea can be extended: Noether's \htmladdnormallink{theorem}{http://planetphysics.us/encyclopedia/Formula.html} shows that every continuous symmetry of a \htmladdnormallink{physical law}{http://planetphysics.us/encyclopedia/PrincipleOfCorrespondingStates.html} that can be formulated as an action principle leads to a conserved quantity. In this setting, momentum can be viewed as the conserved quantity corresponding to spatial translations. This notion of momentum can be generalised in such a way that it is also possible to speak of the momentum of, for example, electromagnetic \htmladdnormallink{waves}{http://planetphysics.us/encyclopedia/CosmologicalConstant.html}.
Momentum plays an important role in the \htmladdnormallink{Hamiltonian}{http://planetphysics.us/encyclopedia/Hamiltonian2.html} formalism of classical mechanics, where mechanical systems are described in terms of generalised coordinates and generalised momenta. This, in turn, explains the appearance of the momentum \htmladdnormallink{operator}{http://planetphysics.us/encyclopedia/QuantumSpinNetworkFunctor2.html} in the Schr\"odinger equation in \htmladdnormallink{quantum mechanics}{http://planetphysics.us/encyclopedia/QuantumParadox.html}.
A quantity related to momentum is \emph{impulse}, which is defined as the force exerted on a moving object integrated over a time interval $[t_0,t_1]$: $$ \mathbf{I}\equiv\int_{t_0}^{t_1}\mathbf{F}(t)\,\mathrm{d}t. $$ By integrating the two sides of Newton's second law over time, we obtain the equation $$ \mathbf{I}=\mathbf{p}(t_1)-\mathbf{p}(t_0). $$ In words: the impulse is equal to the change in momentum.
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