In this case, the admissible states are not required to meet any of the field equations or boundary conditions.
Let
denote the set of all admissible states and let
be
a functional on
defined by
![{\displaystyle {\mathcal {W}}[s]=\int _{\mathcal {B}}U({\boldsymbol {\varepsilon }})-\int _{\mathcal {B}}{\boldsymbol {\sigma }}:{\boldsymbol {\varepsilon }}~dV-\int _{\mathcal {B}}({\boldsymbol {\nabla }}\bullet {\boldsymbol {\sigma }}+\mathbf {f} )\bullet \mathbf {u} ~dV+\int _{\partial {\mathcal {B}}^{u}}\mathbf {t} \bullet {\widehat {\mathbf {u} }}~dA+\int _{\partial {\mathcal {B}}^{t}}(\mathbf {t} -{\widehat {\mathbf {t} }})\bullet \mathbf {u} ~dA}](https://wikimedia.org/api/rest_v1/media/math/render/svg/75e1057fc5e4bcc0b87c6490cd92404fd6e23b0d)
for every
.
Then,
![{\displaystyle \delta {\mathcal {W}}[s]=0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/d191b3f1ee1174c46e62f38c10c0bc31f7ace248)
at an admissible state
if and only if
is a solution of the mixed problem.