Talk:Web Science/Part2: Emerging Web Properties/Advanced statistical descriptive models for the Web/Fitting a curve on a log log plot/quiz

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about question number 2[edit source]

in my opinion the answer has to be 6√2 . why 6? [(6^2)+(6^2)]^(1/2) = 6√2 --141.26.69.70 (discuss) 20:28, 3 December 2016 (UTC)Reply

why would you do this calculation? We are now in a function space and not calculating the length of a two dimensional vector. --Renepick (discusscontribs) 18:19, 4 December 2016 (UTC)Reply

Problem in first 3 question[edit source]

Not getting how this answer comes ? Can you please explain these 3 calculation ? --141.26.69.70 (discuss) 11:30, 4 December 2016 (UTC)Reply

have a look at the other question and my reply there. --Renepick (discusscontribs) 18:18, 4 December 2016 (UTC)Reply
||f(x)||_1=integral_from0_to6(x dx)= x^2 /2 | 6 0 =36/2 - 0 =18 . To check the logics you always can think of integral as an area under the line. In this case it is an area (triangle with sizes 6 and 6) under the line y=x, which is limited from 0 to 6. The area is 6*6 /2=18 . I hope my answer helped. Cheers, Olya --95.91.218.94 (discuss) 22:27, 4 December 2016 (UTC)Reply

Question 3[edit source]

By the rules of vector norm ... |x|_p=(sum_(i)|x_i|^p)^(1/p).

the answer should be 21 not 18 as we are summing up from 0 to 6 which sums up to 21 by the rules ... what I'm getting wrong here that makes my answer 21 and the correct answer is 18 ? --Omar K. Aly (discusscontribs) 17:46, 4 December 2016 (UTC)Reply

If you watch the video carefully you will find a definition for the L_1 norm for continues and discrete functions. In the video we are discussing a discrete function for which the L1 norm ist calculated in a similar way as for finite dimensional vectors. In the exercise we have a function defined on an entire interval so you need to integrate the function and not just sum up the values 1,2,3,4,5 and 6. --Renepick (discusscontribs) 18:17, 4 December 2016 (UTC)Reply
Okay so its a definite integral for x with a=0 and b = 6, Thank you Rene --Omar K. Aly (discusscontribs) 00:16, 5 December 2016 (UTC)Reply