Nonlinear finite elements/Homework11/Solutions/Problem 1/Part 8
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Problem 1: Part 8: Consistency condition - 2 [edit]
The yield stress
is given by the Johnson-Cook model
where
is the initial yield stress,
are constants,
is a reference temperature, and
is the melt temperature. Derive expressions for
, and
for the von Mises yield condition with the Johnson-Cook flow stress model.
The yield function is
Therefore,
and
![\sigma_y(\alpha,T) = \left[\sigma_0 + B \alpha^n\right]
\left[1 - \left(\cfrac{T - T_0}{T_m -T_0}\right)\right]](http://upload.wikimedia.org/math/f/7/c/f7cbc76d40e8cc0bcd63fbcf1a62bd7c.png)
![f = \sqrt{\cfrac{3}{2}}~\sqrt{\mathbf{s}:\mathbf{s}} - \sigma_y=
\sqrt{\cfrac{3}{2}}~\sqrt{\mathbf{s}:\mathbf{s}} - \left[\sigma_0 + B \alpha^n\right]
\left[1 - \left(\cfrac{T - T_0}{T_m -T_0}\right)\right]](http://upload.wikimedia.org/math/f/9/7/f977a6cc935a2056f8253d904747c5e3.png)
![{
\frac{\partial f}{\partial \alpha} = f_{\alpha} = - n~B~\alpha^{n-1}
\left[1 - \left(\cfrac{T - T_0}{T_m -T_0}\right)\right]
}](http://upload.wikimedia.org/math/f/6/5/f65c27aad9cd16e9617892a8c5fccf13.png)
![{
\frac{\partial f}{\partial T} = f_T = \left(\cfrac{1}{T_m - T_0}\right)
\left[\sigma_0 + B \alpha^n\right] ~.
}](http://upload.wikimedia.org/math/1/b/b/1bb420b1f8b752479afe44be4030f49a.png)