Mesh Analysis/Answers

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Exercise 8: Answers


EE-102-L08-Fig4-Final.jpg

Model Answer

KVL arround abca loop:

I1 * R1 + (I1I3) * R2 + (I1I2) * R3 =  − Vs

Therefore

I1(R1 + R2 + R3) − I2(R3) − I3(R2) =  − Vs   ...............   (1)


KVL arround abda loop:

 (I2I1) * R3 + (I2I3) * R4 + I2 * R5 = Vs

Therefore

I1(R3) + I2(R3 + R4 + R5) − I3(R4) = Vs   ...............   (2)


KVL arround bcdb loop:

 I3 * R6 + (I3I2) * R4 + (I3I1) * R2 = 0

Therefore

I1(R2) − I2(R4) + I3(R2 + R4 + R6) = 0   ...............   (3)

Now we can create a matrix with the above equations as follows:

 \begin{bmatrix} (R_1 +R_2 + R_3) & (-R_3) & (-R_2) \\ (-R_3) & (R_3 +R_4 + R_5) & (-R_4) \\ (-R_2) & (-R_4) & (R_2 +R_4 + R_6)\end{bmatrix} . \begin{bmatrix} I_1\\ I_2 \\ I_3 \end{bmatrix} = \begin{bmatrix} -V_s \\ V_s \\ 0 \end{bmatrix}

The following matrix is the above with values substituted:

 A.\vec{X} = \vec{Y}\begin{bmatrix} 10220& -10 000 & -20 \\ -10 000& 30 000 & -5000 \\ -20 & -5000 & 6020 \end{bmatrix} . \begin{bmatrix} I_1\\ I_2 \\ I_3 \end{bmatrix} = \begin{bmatrix} -9 \\ 9  \\ 0 \end{bmatrix}


Now that we have arranged equations 1; 2 & 3 into a matrix we need to get Determinants of the General matrix, and Determinants of alterations of the general matrix as follows:

Solving determinants of:

  • Matrix A  : General matrix A from KVL equations
  • Matrix A1 : Genral Matrix A with Column 1 substituted by \vec Y.
  • Matrix A2 : Genral Matrix A with Column 2 substituted by \vec Y.
  • Matrix A3 : Genral Matrix A with Column 3 substituted by \vec Y.

As follows:

det A = 9.86 \times 10^{11}
detA1 =  − 857700000
detA2 = 11016000
detA3 = 6300000


Now we can use the solved determinants to arrive at solutions for Mesh Currents I1;I2andI3 as follows:


1. I_1 = \frac{det A1}{det A} = -0.00086968A

2. I_2 = \frac{det A2}{det A} = 0.00001117A

3. I_3 = \frac{det A3}{det A} = 0.000006388A

Now we can solve for the current through R3 as follows:

I_{R_3} = I_1 - I_2 = -0.881mA 

The negative sign means that I_{R_3} is flowing in the direction of I2.