Continuum mechanics/Leibniz formula

The Leibniz rule The integral $F(t)=\int _{a(t)}^{b(t)}f(x,t)~{\text{dx}}$ is a function of the parameter $t$. Show that the derivative of $F$ is given by ${\cfrac {dF}{dt}}={\cfrac {d}{dt}}\left(\int _{a(t)}^{b(t)}f(x,t)~{\text{dx}}\right)=\int _{a(t)}^{b(t)}{\frac {\partial f(x,t)}{\partial t}}~{\text{dx}}+f[b(t),t]~{\frac {\partial b(t)}{\partial t}}-f[a(t),t]~{\frac {\partial a(t)}{\partial t}}~.$ This relation is also known as the Leibniz rule.

Proof:

We have,

${\cfrac {dF}{dt}}=\lim _{\Delta t\rightarrow 0}{\cfrac {F(t+\Delta t)-F(t)}{\Delta t}}~.$

Now,

${\begin{aligned}{\cfrac {F(t+\Delta t)-F(t)}{\Delta t}}&={\cfrac {1}{\Delta t}}\left[\int _{a(t+\Delta t)}^{b(t+\Delta t)}f(x,t+\Delta t)~{\text{dx}}-\int _{a(t)}^{b(t)}f(x,t)~{\text{dx}}\right]\\&\equiv {\cfrac {1}{\Delta t}}\left[\int _{a+\Delta a}^{b+\Delta b}f(x,t+\Delta t)~{\text{dx}}-\int _{a}^{b}f(x,t)~{\text{dx}}\right]\\&={\cfrac {1}{\Delta t}}\left[-\int _{a}^{a+\Delta a}f(x,t+\Delta t)~{\text{dx}}+\int _{a}^{b+\Delta b}f(x,t+\Delta t)~{\text{dx}}-\int _{a}^{b}f(x,t)~{\text{dx}}\right]\\&={\cfrac {1}{\Delta t}}\left[-\int _{a}^{a+\Delta a}f(x,t+\Delta t)~{\text{dx}}+\int _{a}^{b}f(x,t+\Delta t)~{\text{dx}}+\int _{b}^{b+\Delta b}f(x,t+\Delta t)~{\text{dx}}-\int _{a}^{b}f(x,t)~{\text{dx}}\right]\\&=\int _{a}^{b}{\cfrac {f(x,t+\Delta t)-f(x,t)}{\Delta t}}~{\text{dx}}+{\cfrac {1}{\Delta t}}\int _{b}^{b+\Delta b}f(x,t+\Delta t)~{\text{dx}}-{\cfrac {1}{\Delta t}}\int _{a}^{a+\Delta a}f(x,t+\Delta t)~{\text{dx}}~.\end{aligned}}$

Since $f(x,t)$ is essentially constant over the infinitesimal intervals $a<x<a+\Delta a$ and $b<x<b+\Delta b$, we may write

${\cfrac {F(t+\Delta t)-F(t)}{\Delta t}}\approx \int _{a}^{b}{\cfrac {f(x,t+\Delta t)-f(x,t)}{\Delta t}}~{\text{dx}}+f(b,t+\Delta t)~{\cfrac {\Delta b}{\Delta t}}-f(a,t+\Delta t)~{\cfrac {\Delta a}{\Delta t}}~.$

Taking the limit as $\Delta t\rightarrow 0$, we get

$\lim _{\Delta t\rightarrow 0}\left[{\cfrac {F(t+\Delta t)-F(t)}{\Delta t}}\right]=\lim _{\Delta t\rightarrow 0}\left[\int _{a}^{b}{\cfrac {f(x,t+\Delta t)-f(x,t)}{\Delta t}}~{\text{dx}}\right]+\lim _{\Delta t\rightarrow 0}\left[f(b,t+\Delta t)~{\cfrac {\Delta b}{\Delta t}}\right]-\lim _{\Delta t\rightarrow 0}\left[f(a,t+\Delta t)~{\cfrac {\Delta a}{\Delta t}}\right]$

or,

${{\cfrac {dF(t)}{dt}}=\int _{a(t)}^{b(t)}{\frac {\partial f(x,t)}{\partial t}}~{\text{dx}}+f[b(t),t]~{\frac {\partial b(t)}{\partial t}}-f[a(t),t]~{\frac {\partial a(t)}{\partial t}}~.}\qquad \qquad \qquad \square$

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